What is the diagonal measurement in feet and inches for a rectangular structure that is 60' - 9" long by 42' - 6" wide?

To find the diagonal measurement of a rectangular structure, the Pythagorean theorem is utilized. This theorem states that in a right triangle, the square of the length of the hypotenuse (diagonal in this case) is equal to the sum of the squares of the other two sides (length and width).

First, convert the dimensions of the rectangular structure into a single unit (inches). The length of 60' - 9" can be converted to inches:

• 60 feet = 60 * 12 = 720 inches

• 9 inches remains as is

• So, the total length in inches is 720 + 9 = 729 inches.

For the width of 42' - 6":

• 42 feet = 42 * 12 = 504 inches

• 6 inches remains as is

• Therefore, the total width in inches is 504 + 6 = 510 inches.

Now apply the Pythagorean theorem:

Diagonal² = Length² + Width²

Diagonal² = 729² + 510².

Calculating these values:

729² = 531441

510² = 260100

So,

Diagonal² = 531441 +