What is the weight of a #5 deformed bar in pounds?

The weight of a #5 deformed bar is determined by its diameter and the density of steel, which is typically around 490 pounds per cubic foot. A #5 bar has a nominal diameter of 5/8 inch (or 0.625 inches).

To calculate the weight, you can use the formula:

Weight (lbs) per foot = (Area of the bar in square inches) × (Length in feet) × (Density of steel)

For a #5 rebar, the area is approximately 0.31 square inches. Using the density of steel at 490 lbs/ft³, the weight of a 12-inch (1-foot) piece can be calculated as follows:

1. Convert the area into cubic feet:

• 0.31 sq. in. is equal to 0.31/144 sq. ft. since there are 144 square inches in a square foot.

2. Multiply this area by the density of steel and a 1-foot length to find the total weight.

After performing these calculations, the weight of a #5 deformed bar comes out to approximately 1.043 pounds per foot. Therefore, the correct answer aligns with that calculated weight.